1.

A particle executing SHM has an acceleration of 64cm//s^(2) with its displacement is 4 cm. Its time period, in seconds is……………

Answer»

`(PI)/(2)`
`(pi)/(4)`
`pi`
`2pi`

Solution :`a=omega^(2)yimpliesomega=sqrt((a)/(y))impliesT=2pisqrt((y)/(a))=2pisqrt((4)/(64))=(pi)/(2)`


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