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A particle executing SHM of amplitude 4 cm and `T=4 s` .The time taken by it to move from positive extreme position to half the amplitude isA. 0.5 sB. `2//3` sC. 0.75 sD. 1 s |
Answer» Correct Answer - B `x=Acosomegat" "(A)/(2)=Acosomegat` `thereforeomegat=cos^(-1)((1)/(2))" "therefore (2pi)/(T)t=(pi)/(3)` `t=(4)/(3xx2)=(2)/(3)s` |
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