1.

A particle executing SHM of amplitude 4 cm and `T=4 s` .The time taken by it to move from positive extreme position to half the amplitude isA. 0.5 sB. `2//3` sC. 0.75 sD. 1 s

Answer» Correct Answer - B
`x=Acosomegat" "(A)/(2)=Acosomegat`
`thereforeomegat=cos^(-1)((1)/(2))" "therefore (2pi)/(T)t=(pi)/(3)`
`t=(4)/(3xx2)=(2)/(3)s`


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