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A particle executing SHM passes through the mean position with a velocity of `4 ms^(-1)`. The velocity of the particle at a point where the displacement is half of the amplitude isA. `2 ms^(-1)`B. `2sqrt(3)ms^(-1)`C. `sqrt(3)ms^(-1)`D. `1ms^(-1)` |
Answer» Correct Answer - B `V=(Aomegasqrt(3))/(2)=(4sqrt(3))/(2)=2sqrt(3)ms^(-1)` |
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