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A particle executing SHM. The phase difference between acceleration and displacement is |
Answer» Correct Answer - C Let the displacement of a particle executing simple harmonic motion at any instant t is, `x=Acosomegat` velocity, `v=(dx)/(dt)=(d)/(dt)(Acosomegat)=-Aomegasinomegat` Acceleration, `a=(dv)/(dt)=-Aomega^(2)cosomegat=Aomega^(2)cos(omegat+pi)` Phase of displacement, `phi_(1)=omegat` phase of acceleration, `phi_(2)=omegat+pi` `therefore`Phase difference`=phi_(2)-phi_(1)=(omegat+pi)-omegat=pi` |
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