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A particle executing SHM. The phase difference between acceleration and displacement is

Answer» Correct Answer - C
Let the displacement of a particle executing simple harmonic motion at any instant t is, `x=Acosomegat`
velocity, `v=(dx)/(dt)=(d)/(dt)(Acosomegat)=-Aomegasinomegat`
Acceleration, `a=(dv)/(dt)=-Aomega^(2)cosomegat=Aomega^(2)cos(omegat+pi)`
Phase of displacement, `phi_(1)=omegat`
phase of acceleration, `phi_(2)=omegat+pi`
`therefore`Phase difference`=phi_(2)-phi_(1)=(omegat+pi)-omegat=pi`


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