A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is…………….

A particle executing simple harmonic motion of amplitude 5 cm has maxi

1.	A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is…………….
Answer» 3Hz 2 HZ 4Hz 1 Hz Solution :`A=5 cm = 5 xx 10^(-2)m ,UPSILON = (max )= 31.4cm//s= 31.4xx 10^(-2) m//s` MAXIMUMSPEED`V_(max)= 2 pietaxx A ` ` thereforen =(V_(max))/( 2PI A )= ( 31.4 xx 10^(-2) )/( 2 pixx 5XX 10^(-2)) =( 31.4 )/( 10 xx3.14) = n=1 Hz`