A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm"/"s. The frequency of its oscillation is……….

A particle executing simple harmonic motion of amplitude 5 cm has maxi

1.	A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm"/"s. The frequency of its oscillation is……….
Answer» 4 Hz 3 Hz 2 Hz 1 Hz Solution :From maximum velocity in SHM, `v_("MAX")= A omega = A(2pi f)` `therefore f= (v_("max"))/(2pi A)` `=(31.4)/(2(3.14)(5))= 1Hz`.