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A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm / s . The frequency of its oscillation isA. 3 HzB. 2 HzC. 4 HzD. 1 Hz |
Answer» Correct Answer - D Given, A = 5 cm and `V_(max) = 314 cms^(-1)` `rArr" "A omega = 31.4 rArr omega = (31.4)/(5)` `rArr" "2 pi v = (31.4)/(5) rArr v = (31.4)/(2 xx 31.4 xx 5) = 1 Hz` |
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