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A particle exeriences constant acceleration form ` 20 seconds after strating from gest. If it travels a distance ` S_(1)` in the first ` 10 seconds` and distance ` S_(2)` in the next 10 seconds`. Find the relation between ` S_(1) and S_(@)`. |
Answer» Hence, ` u =0 , t= 10 s , a=a (say ) , S=S_(1)` As, S=ut + 1/2 at ^(2)` :. S_(1) =0 xx 10 + 1/2 a xx 10^(2) =50 a ` ….(i) Taking motion of particle for ` 10 s + 10 s = 20 s`, we have `(S_(1) + S_(2) ) =0 xx 20 + 1/2 a xx 20^(2) = 200 a ` ...(ii) :. S_(2) =(S_(1) + S_(2)) - S_(1) =200 a- 50 a` :. ` S_(2)/S_(1) = (150 a)/(50 A) =3 or S_(2) =3 S_(1)`. |
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