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A particle has an initial velocity of `4 hati +3 hatj` and an acceleration of `0.4 hati + 0.3 hatj`. Its speed after 10s isA. 10 unitsB. 7 unitsC. `7 sqrt(2)` unitsD. 8.5 units |
Answer» Correct Answer - A `v = u + at = (4hati +3hatj) +(0.4 hati + 0.3hatj) (10) = (8hati +6hatj)` `:. v = sqrt((8)^(2) +(6)^(2)) = 10` units |
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