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A particle has displacement of 12 m towards east and 5m towards north then 6 m vertically upward. The sum of these displacements is (1) 12. (2) 10.04 m. (3) 14.31 m (4) none of these |
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Answer» Answer is (3) 14.31 m S = S1 + S2 + S3 S = √(S12 + S22 + S32) ⇒ S = √(122 + 52 + 62) = 14.31 m |
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