A particle having a charge of `q=8.85muC` is placed on the axis of a circular ring of radius `R=30cm` at a point `P` at a distance of `a=40cm` from the centre of the ring.The electric flux passing through the ring is `x xx 10^(5)N//C` .Find the value of `x`?

A particle having a charge of `q=8.85muC` is placed on the axis of a c

1.	A particle having a charge of `q=8.85muC` is placed on the axis of a circular ring of radius `R=30cm` at a point `P` at a distance of `a=40cm` from the centre of the ring.The electric flux passing through the ring is `x xx 10^(5)N//C` .Find the value of `x`?
Answer» Correct Answer - 1 `phi_(E)= phi_(E)=(q)/(2epsilon_(0))(1-(a)/(sqrt(R^(2)+a^(2))))` ` rArr phi_(E)=(8.85xx10^(-6))/(2(8.85xx10^(-12)))(1-(40)/(50))` `rArr phi_(E)=(10^(6))/(2)(1-(4)/(5))` `rArr phi_(E)=1xx10^(5)=x xx 10^(5)x=1`

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A particle having a charge of `q=8.85muC` is placed on the axis of a circular ring of radius `R=30cm` at a point `P` at a distance of `a=40cm` from the centre of the ring.The electric flux passing through the ring is `x xx 10^(5)N//C` .Find the value of `x`?

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