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A particle having initial velocity 4 m/s moves with a constant acceleration `1m//s^(2)` for a time interval of 10 second in straight line. Find the displacement of the particle in the last second and the distance travelled in 10 second.

Answer» Here, `u=4m//s, a=1m//s^(2), s_(10)^(th)=?, s_(10)=?`
As, `s_(10)^(th)=u+(1)/(2)a(2t-1)=4+(1)/(2)xx1(2xx10-1)=4+(1)/(2)xx19`
`=4+9.5=13.5m`
`s_(10)=ut+(1)/(2)at^(2)=4(10)+(1)/(2)xx1xx1(10)^(2)`
`=40+(1)/(2)xx100=90m`


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