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A particle in a certain conservative force field has a potential energy given by U= (20 xy)/(z). The force exerted on it is

Answer»

`((20 y)/(Z)) hati + ((20x)/(z))hatj + ((20 xy)/(z^2))hatk`
`-((20 y)/(z)) hati - ((20x)/(z))hatj + ((20 xy)/(z^2))hatk`
`-((20 y)/(z)) hati - ((20x)/(z))hatj - ((20 xy)/(z^2))hatk`
`((20 y)/(z)) hati + ((20x)/(z))hatj - ((20 xy)/(z^2))hatk`

SOLUTION :Given `U = (20 xy)/(z)`
For a CONSERVATIVE field, `vecF = -vec(nabla)U`
where , `vec(nabla) = hati (DEL)/(del x)+ hatj (del)/(del y) + hatk (del)/(del k)`
`:. vecF = -[hati (del U)/(del x) + hatj (del U)/(del y) + hatk (del U)/(delz)]`
`= - [hati (del)/(del x) ((20xy)/(z)) + hatj (del)/(del y)((20 xy)/(z)) + hatk (del)/(del z) ((20 xy)/(z))]`
`= -((20y)/(z)) hati - ((20 x)/(z)) hatj + ((20 xy)/(z^2) hatk`.


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