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A particle in SHM has a period of 4s .It takes time `t_(1)` to start from mean position and reach half the amplitude. In another case it takes a time `t_(2)` to start from extreme position and reach half the amplitude. Find the ratio `t_(1)//t_(2)`A. `(t_(1))/(t_(2))`B. `(t_(1))/(t_(2))`C. `(t_(1))/(t_(2)) =2`D. `(t_(1))/(t_(2)) = 3` |
Answer» Correct Answer - B `(A)/(2) = A sin (omegat_(1)), (A)/(2) = A cos (omegat_(2))` |
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