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A particle is acted upon by constant forces 4hati+hatj-3hatk and 3hati+hatj-hatk which displace it from a point hati+2hatj+3hatk to the point 5hati+4hatj+hatk. The work done in standard units by the forces is given by |
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Answer» 40 units `F = 7hati +2hatj- 4hatk` The PARTICLEIS displacedfrom `A(hati + 2hatj + 3hatk) - (hati + 2hatj + 3hatk) = 4hati +2hatj- 2HATK` `:.` Work DONE`= F . AB=(7hati + 2hatj - 4hatk ). (4hati + 2hatj - 2hatk)` `= 28 + 4+ 8 = 40` units |
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