1.

A particle is acted upon by constant forces 4hati+hatj-3hatk and 3hati+hatj-hatk which displace it from a point hati+2hatj+3hatk to the point 5hati+4hatj+hatk. The work done in standard units by the forces is given by

Answer»

40 units
30 units
25units
15 units

Solution :TOTAL force, `F = (4hati + hatj - 3hatk) + (3hati + hatj- hatk)`
`F = 7hati +2hatj- 4hatk`
The PARTICLEIS displacedfrom
`A(hati + 2hatj + 3hatk) - (hati + 2hatj + 3hatk) = 4hati +2hatj- 2HATK`
`:.` Work DONE`= F . AB=(7hati + 2hatj - 4hatk ). (4hati + 2hatj - 2hatk)`
`= 28 + 4+ 8 = 40` units


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