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A particle is at x=+5m at t=0, x=-7m at t=6s and x=+2m at t=10s. Find the average velocity of the particle during the intervals (a) t=0 to t=6s (b) t=6s to t=10s (c ) t=0 to t=10s.

Answer» <html><body><p></p>Solution :From the <a href="https://interviewquestions.tuteehub.com/tag/definition-11288" style="font-weight:bold;" target="_blank" title="Click to know more about DEFINITION">DEFINITION</a> of <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=(Deltax)/(Deltat)=(x_(2)-x_(1))/(t_(2)-t_(1))` <br/> (a) The average velocity between the times `t=0` to `t=6s` `x_(1)=+5m,t_(1)=0,x_(2)=-7mt_(2)=6s` <br/> Hence `v_(1)=(x_(2)-x_(1))/(t_(2)-t_(1))=(-7-5)/(6-0)=-2ms^(-1)` <br/> (b) The average velocity between the times `t_(2)=6s` to `t_(3)=<a href="https://interviewquestions.tuteehub.com/tag/10s-267218" style="font-weight:bold;" target="_blank" title="Click to know more about 10S">10S</a>` is <br/> `v_(2)=(x_(3)-x_(2))/(t_(3)-t_(2))=(2-(-7))/(10-6)=(9)/(4)=2.25ms^(-1)` <br/> (c ) The average velocity between times `t_(1)=0` to `t_(3)=10s` is `v_(3)=(x_(3)-x_(1))/(t_(3)-t_(1))=(2-5)/(10-0)=-0.3ms^(-1)`</body></html>


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