A particle is displaced from (1,2) m to (0,0) m along the path y=2x3. Work done by a force →F=(x3^j+y^i) N acting on the particle, during this displacement is (in J)[Give your answer without considering sign]

A particle is displaced from (1,2) m to (0,0) m along the path y=2x3.

1.	A particle is displaced from (1,2) m to (0,0) m along the path y=2x3. Work done by a force →F=(x3^j+y^i) N acting on the particle, during this displacement is (in J)[Give your answer without considering sign]
Answer» A particle is displaced from $(1, 2) m$ to $(0, 0) m$ along the path $y = 2 x^{3}$ . Work done by a force $\to F = (x^{3}^j + y^i) N$ acting on the particle, during this displacement is (in $J$ ) [Give your answer without considering sign]

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A particle is displaced from (1,2) m to (0,0) m along the path y=2x3. Work done by a force →F=(x3^j+y^i) N acting on the particle, during this displacement is (in J)[Give your answer without considering sign]

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