1.

A particle is dropped under gravity from rest from a height `h(g = 9.8 m//sec^2)` and it travels a distance `9h//25` in the last second, the height `h` is.A. 100 mB. `12.5 m`C. 145 mD. `167.5 m`

Answer» Correct Answer - B
Let h be distance covered in t second `rArr h=(1)/(2)g t^(2)`
Distance covered in t th second `=(1)/(2)g(2t-1)`
`rArr (9h)/(25)=(g)/(2)(2t-1)`
From above two equations, `h=122.5 m`


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