1.

A particle is executing `SHM`. It passes through mean position at the instant `t = 0`. At what instants the speed of it is `50%` of its maximum speed?

Answer» `v = v_(max) cos (omega t) rArr (v_(max))/(2) = v_(max) cos ((2pi)/(T)t)`
`t = (T)/(2pi) cos^(-2) (+-(1)/(2))`


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