A particle is executing SHM with amplitude A. At what distance from mean position will the KE and PE are equal ?

A particle is executing SHM with amplitude A. At what distance from me

1.	A particle is executing SHM with amplitude A. At what distance from mean position will the KE and PE are equal ?
Answer» SOLUTION :SINCE KE = PE, `1/2 mv^2 =1/2 m omega^2 x^2 implies1/2 m omega^2 (A^2 - x^2) =1/2 m omega^2 x^2` `impliesA^2 - x^2 = x^2 ` (or) `x= A/(sqrt2)`