A particle is in circular motion with an acceleration alpha=0.2rads^(-2). (a) What is the angular displacement made by the particle after 5 s? (b) What is the angular velocity at 15 s?. Assume the initial angular velocity is zero.

A particle is in circular motion with an acceleration alpha=0.2rads^(-

1.	A particle is in circular motion with an acceleration alpha=0.2rads^(-2). (a) What is the angular displacement made by the particle after 5 s? (b) What is the angular velocity at 15 s?. Assume the initial angular velocity is zero.
Answer» Solution :SINCE the initial ANGULAR velocity is zero `(omega_(0)=0)`. The angular displacement made by the particle is given by `THETA=omega_(o)t+(1)/(2)alphat^(2)` `theta=(1)/(2)xx2xx10^(-1)xx25=2.5` RAD In terms of degree `theta=2.5xx57.17^(@)~~143^(@)`