A particle is movbed from `(0, 0) to (a, a)` under a force `F =(x^(2)hati+y^(3)hatj)` from two paths. Path 1 si `OP` and Path 2 is `OQP`. Let `W_(1)` and `W_(2)` be the work done by this force in these two paths. Then A. `W_(1)=W_(2)`B. `W_(1)=2W_(2)`C. `W_(2)=2W_(2)`D. `W_(2)=4W_(1)`

A particle is movbed from `(0, 0) to (a, a)` under a force `F =(x^(2)h

1.	A particle is movbed from `(0, 0) to (a, a)` under a force `F =(x^(2)hati+y^(3)hatj)` from two paths. Path 1 si `OP` and Path 2 is `OQP`. Let `W_(1)` and `W_(2)` be the work done by this force in these two paths. Then A. `W_(1)=W_(2)`B. `W_(1)=2W_(2)`C. `W_(2)=2W_(2)`D. `W_(2)=4W_(1)`
Answer» Correct Answer - A A particle………… The force is constant and hence conservative `:. W_(1) = W_(2)`

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A particle is movbed from `(0, 0) to (a, a)` under a force `F =(x^(2)hati+y^(3)hatj)` from two paths. Path 1 si `OP` and Path 2 is `OQP`. Let `W_(1)` and `W_(2)` be the work done by this force in these two paths. Then A. `W_(1)=W_(2)`B. `W_(1)=2W_(2)`C. `W_(2)=2W_(2)`D. `W_(2)=4W_(1)`

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