A particle is moving along a horizontal circle with a speed V = at - bt^(3). Then angular displacement of particle at any instant is (consider at t=0 , theta_(0) = 0and 'r' is radius of circle and theta is angular displacement at any instant)

A particle is moving along a horizontal circle with a speed V = at - b

1.	A particle is moving along a horizontal circle with a speed V = at - bt^(3). Then angular displacement of particle at any instant is (consider at t=0 , theta_(0) = 0and 'r' is radius of circle and theta is angular displacement at any instant)
Answer» `theta= (at^(2))/(2r)- (bt^(4))/(4R)` `theta= (at^(3))/(6R)-(bt^(4))/(3r)` `theta= (at)/(2r)-(bt^(2))/(3r)` `theta= (at)/(r)-(bt^(3))/(r)` Answer :A