A particle is moving along a horizontal circle Y under a centripetal force where (-c)/(r^(2))is a constant. Then, the total energy of the particle is

A particle is moving along a horizontal circle Y under a centripetal f

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1.	A particle is moving along a horizontal circle Y under a centripetal force where (-c)/(r^(2))is a constant. Then, the total energy of the particle is
Answer» `(-C)/(2R^(2))` `(c)/(2r)` `(-c)/(2r)` `(c)/(2r^(2))` ANSWER :C