A particle is moving along a straight line parallel to x-axis with constant velocity. Its angular momentum about the origin

A particle is moving along a straight line parallel to x-axis with con

1.	A particle is moving along a straight line parallel to x-axis with constant velocity. Its angular momentum about the origin
Answer» decreases with time increases with time remains constant is zero Solution :Suppose the PARTICLES of mass m is moving with speed v parallel to x AXIS as shown in figure , then at any time t , coordinates of P will be `x = vt , y = b ` and z = 0 while COMPONENTS of velocity will be `v_(x)= v , v_(y) = 0 ` and `v_(z) = 0` (as it is moving parallel to x-axis) So , `vecL` So , `vecL = vecr xx vecp = m \|{:(hati , hatj , hatk) , (vt , b , 0), (v , 0 ,0):}\| = hatk m[vt xx0 - vb] =-mvb hatk` i.e., angular momentum has magnitude mvb and is directed along NEGATIVE z-axis i.e., angular momentum remains constant .