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A particle is moving along straight line with initial velocity `+7m//sec` and uniform acceleration `-2m//sec^(2)` . The distance travlled by the particle in `4th` second of its motion is:A. `0`B. `0.25m`C. `0.5m`D. `7m` |
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Answer» Correct Answer - C A particle……… Distance travelled `= |S_(3-3.5)|+|S_(3.5-4)|` `|(1+0)/(2)xx0.5|+|(0+(-1))/(2)xx0.5|=0.25+0.25` `= 0.5m`. |
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