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A particle is moving along x-axis. Its X-coordinate varies with time as, `X=2t^2+4t-6` Here, X is in metres and t in seconds. Find average velocity between the time interval `t=0 to t=2s.`

Answer» In 1-D motion, average velocity can be written as
`v_(av)=(Delta s)/(Delta t)=(X_f-X_i)/(Delta t)=(X_(2 sec)-X_(0 sec))/(2-0)`
`=([2(2)^2+4(2)-6]-[2(0)^2+4(0)-6])/2`
`=8m//s`


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