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A particle is moving eastwards with a velocity of 5 m/s. In 10s the velocity changes to 5 m/s northwards. The average acceleration in this time is

Answer»

zero
`(1)/(SQRT2)m/s^(2)` towards north-west
`(1)/(sqrt2)m/s^(2)` towards north-east
`(1)/(2)m/s^(2)` towards north-west

Solution :`veca= (dvecv)/(DT)=(5)/(10)(hatj-hati)`
`a=(1)/(sqrt2)MS^(-2)`


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