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A particle is moving in a circel of radius `R = 1m` with constant speed `v =4 m//s`. The ratio of the displacement to acceleration of the foot of the perpendicular drawn from the particle onto the diameter of the circel isA. `(1)/(16)s^(2)`B. `(1)/(2)s^(2)`C. `2s^(2)`D. `16s^(2)` |
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Answer» Correct Answer - A `omega =(v)/(R ) , (x)/(a) = (1)/(omega^(2))` |
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