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A particle is moving in a circle of radius R=1 m with constant speed v=4m//s. The ratio of the displacement to acceleration of the foot of the perpendicular drawn from the particle onto the diameter of the circle is |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>)s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(1)/(2)s^(2)`<br/>`2s^(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/16s-277872" style="font-weight:bold;" target="_blank" title="Click to know more about 16S">16S</a>^(2)`</p>Answer :A</body></html> | |