Saved Bookmarks
| 1. |
a particle is moving in a straight line such that its velocity varies is given by v=10-2t, where v isin the first 8 second. |
|
Answer» Solution :This problem can be solved by drawing the v-t graph. `v=10-2t` `t=0, v=10 m//s` `t=8 s, v=-6 m//s` `v=0implies10-2t=0impliest=5 s` SHAPE: `y=10-2x` (STRAIGHT line) `y=c+mx` `c=10`, +ve `m=-2`, -ve `Area(1)=25, Area(2)=9` The area of the v-t graph gives the DISPLACEMENT//distance Displacement`=25-9-16 m` Displacement`=25+9=34 m` |
|