A particle is moving on a circular path of radius R with constant speed v. During motion of the particle form point A to point B

A particle is moving on a circular path of radius R with constant spee

1.	A particle is moving on a circular path of radius R with constant speed v. During motion of the particle form point A to point B
Answer» Average speed is v/2 The magnitude of average VELOCITY is v/`pi` The magnitude of average ACCELERATION is `(2v^(2))/(piR)` Average velocity is zero. Solution :(a) Average velocity `= ("Displacement") /("Total elapsed TIME") = 2 R// pi R//v = 2v//pi` (B) Average speed `= ("Total distance") /("Total elapsed time") = (piR)/((piR)/v) = v` (C ) Average acceleration `= (v_f -v_i)/ "Total elapsed time" = (2v)/((piR)/v) = (2v^(2))/(piR)`