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A particle is moving on a straight line with constant retardation of `1 m//s^(2)`. Its initial velocity is `10 m//s`.A. The distance travelled by the particle till it comes to rest is 50 m.B. The average velocity till it comes to rest is `5 m//s`.C. It comes to rest in 5 sec.D. Its velocity after 5 sec is `5 m//s` |
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Answer» Correct Answer - A::B::D `0^(2)=u^(2)-2as` `S =(u^(2))/(2a)=(100)/(2)=50m` `v_(ab)=(v+u)/(2)=5m//s` 10 = at t = 10 sec. `v = 10 -1 xx 5 = 5 m//s` |
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