A particle is moving up with balloon with constant accelration (g/8) which starts from rest from ground and at height H particle is droped from balloon. After this event, time for which particle will be in air is sqrt((kH)/(g)). Find the value of k.

A particle is moving up with balloon with constant accelration (g/8) w

1.	A particle is moving up with balloon with constant accelration (g/8) which starts from rest from ground and at height H particle is droped from balloon. After this event, time for which particle will be in air is sqrt((kH)/(g)). Find the value of k.
Answer» SOLUTION :`V^(2)=2XX(9)/(8)H` `v=sqrt(9H)/(2)` Now let time is T `-H=sqrt(9HT)/(2)-(1)/(2)g t^(2)`