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A particle is moving with a constant acceleration `veca = hati-2hatj+2hatk m//s^(2)` and instantaneous velocity `vecv = hati+2hatj+2hatk m//s`, then rate of change of speed of particle 2 second after this instant will be :A. `(19)/(3)m//s^(2)`B. `3m//s^(2)`C. `(19)/(7)m//s^(2)`D. None of these |
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Answer» Correct Answer - C A particle is ………… `vecv=(hati+2hatj+2hatk)+2(hati-2hatj+2hatk)` `= hati +2hatj+2hatk+2hati-4hatj+4hatk` `= 3hati-2hatj+6hatk` `(d|vecv|)/(dt)=((3hati-2hatj+6hatk))/(sqrt(9+4+36))(hati-2hatj+2hatk)` `= (19)/(7)` |
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