1.

A particle is moving with shm in a-straight line. When the distance of the particle from the equilibrium position has the values 2 cm and 4 cm, the corresponding values of velocities are 5 cms^(-1)and 3 cms^(-1)respectively. Find the length of the path and the period.

Answer»


SOLUTION :`T=2pi[x_2^2-x_1^2)//(v_1^2-v_2^2)]^(1//2)=5.4,v_1^2=omega^2(a^2-x_1^2),a=477 ` CM LENGTH ` = 2xx4.77 = 9.54 ` cm


Discussion

No Comment Found