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A particle is moving with SHM in a straight line. When the distance of the particle from the equilibrium position has valuesx_(1) andx_(2), the corresponding value of velocities are u_(1) and x_(1). Show that the time period of oscillation is given by t = 2.... |
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Answer» SOLUTION :When `x= x^(1), V = U^(1) ` when `x = x^(2), v = u^(2) `As`v = omegasqrtA^(2)-x^(2) ` therefore u_(1)=omegasqrtA^(2)-x_(1)^(2) or u_(1)^(2)=OMEGA^(2)(A^(2)-x_(1)^(2)) and u_(2)=omegasqrtA^(2)-x_(2)^(2) or u_(2)^(2)=omega^(2)(A^(2)-x_(2)^(2)) SUBTRACTING (ii) from (i), we get |
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