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A particle is moving with velocity ` vecv = k( y hat(i) + x hat(j)) `, where `k` is a constant . The genergal equation for its path isA. (a) `y^1 = x + constantB. (b) ` xy = cosntant`C. (c ) y^2 = x^2 + constatnD. (d) ` y =x^2 + constant |
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Answer» Correct Answer - C ` vec v = K ( y hat I +x hat j) ` or ` v_x hat i+ v_y hat j = K (y hat i+ x hat j)` :. ` v_x = Ky ` and ` v_y = K x` ` (dx) (dt) = Ky` or ` dx = Ky dt` ,brgt or ` x= Kyt` ….(i) ` (dy)/(dt) = Kx` or ` dy = Kx dt` or ` y= Kxt` ….(ii) From (i0, ` t= x/(Ky)` From (ii), ` y = Kx (x/(Ky)) + a constant ltbRgt or ` y^2 = x^2 + a constant`. |
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