InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A particle is performing harmonic motion if its velocity are `v_(1)` and `v_(2)` at the displecement from the mean position are `y_(1)` and `y_(2)` respectively then its time period isA. `2 pi sqrt((x_(2)^(2) - x_(1)^(2))/(V_(1)^(2) - V_(2)^(2)))`B. `2 pi sqrt((V_(1)^(2) + V_(2)^(2))/(x_(2)^(2) + x_(1)^(2)))`C. `2 pi sqrt((V_(1)^(2) - V_(2)^(2))/(x_(2)^(2) - x_(1)^(2)))`D. `2 pi sqrt((x_(1)^(2) - x_(2)^(2))/(V_(1)^(2) - V_(2)^(2)))` |
|
Answer» `v = omega sqrt(a^(2) - x^(2)) implies v^(2) = omega^(2) (a^(2) - x^(2))` `V_(1)^(2) = omega^(2) (a^(2) - x_(2)^(2)) = omega^(2) a^(2) - omega^(2) x_(2)^(2)` `V_(1)^(2) - V_(2)^(2) = omega^(2) (x_(2)^(2) - x_(1)^(2))` `omega = sqrt((V_(1)^(2) - V_(2)^(2))/(x_(2)^(2) - x_(1)^(2))) implies (2 pi)/(T) = sqrt((V_(1)^(2) - V_(2)^(2))/(x_(2)^(2) - x_(1)^(2))` |
|