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A particle is performing SHM. Its path length is 8 cm, amplitude is4/1 th the path length and time period 0.2s. If the particle is initially in the mean position, the time at which it will be at 1 cm will be |
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Answer» Solution :Length of PATH 2A= 8 CM, A= 4 cm Periodic time `T= 4 XX A`, Time taken to cover distance A is 1 second. `therefore T= 4xx 1 = 4s` Maximum VELOCITY at mean POSITION `therefore v_("max")= A omega` `= 4xx (2pi)/(T) = 4xx (2pi)/(4)` `= 2pi cm s^(-1)`. |
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