A particle is projected at a speed of u = 40 m/s in vertically upward direction in a place where exists a horizontal uniform electric field E0. The specific charge of the particle is `(4g)/(3E_(0))` . (a) Find the time after projection, when speed of the particle will be least. (b) Find the time (after projection) when displacement of the particle becomes perpendicular to its acceleration. (c) Assuming that the particle has been projected from a great height and the electric field is present in large region, what angle the velocity of the particle will make with horizontal after a long time?

A particle is projected at a speed of u = 40 m/s in vertically upward

1.	A particle is projected at a speed of u = 40 m/s in vertically upward direction in a place where exists a horizontal uniform electric field E0. The specific charge of the particle is `(4g)/(3E_(0))` . (a) Find the time after projection, when speed of the particle will be least. (b) Find the time (after projection) when displacement of the particle becomes perpendicular to its acceleration. (c) Assuming that the particle has been projected from a great height and the electric field is present in large region, what angle the velocity of the particle will make with horizontal after a long time?
Answer» Correct Answer - (a). `(36)/(25)s` (b). `(72)/(25)s` (c). `tan^(-1)((3)/(4))`

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