InterviewSolution
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InterviewSolution
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A particle is projected at an angle with horizontal. If `T` is the time of flight and `R` is a horizontal range, then `theta` isA. `cot^(-1)((g T^(2))/(R ))`B. `cot^(-1)((g T^(2))/(2 R ))`C. `tan^(-1)((2R )/(g T^(2)))`D. `tan^(-1)((g T^(2))/(2 R))` |
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Answer» Correct Answer - D `T = (2 u sin theta)/(g), R = (u^(2))/(g).2 sin theta cos theta` `(T^(2))/(R ) = (4 u^(2) sin^(2) theta//g^(2))/(2u^(2) sin theta cos theta//g) = (2 tan theta)/(g)` `tan theta = (g T^(2))/(2 R) rArr theta = tan^(-1)((g T^(2))/(2 R))` |
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