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A particle is projected form a horizontal plane `(x-z` plane) such that its velocity vector at time `t` is gives by `vecV = ahati +(b - ct)hatj`. Its range on the horizontal plane is given byA. `(ba)/c`B. `(2ba)/c`C. `(3ba)/c`D. None |
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Answer» Correct Answer - B `vec(v)=ahat(i)+(b-ct)hat(j)` Time to reach maximum height (when `hat(j)` comp. of velocity becomes zero) `:. B-ct=0rArr t=b/c :.` Time of fight `=(2b)/c` range= horizontal velocity `xx` Time of flight `=axx(2b)/c` |
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