A particle is projected from a tower as shown in figure, then find the distance from the foot of the tower where It will strike the ground. (g = 10 m//s^(2))

A particle is projected from a tower as shown in figure, then find the

1.	A particle is projected from a tower as shown in figure, then find the distance from the foot of the tower where It will strike the ground. (g = 10 m//s^(2))
Answer» Solution :`s = u t + (1)/(2) a t^(2)` `1500 = (500)/(3) sin 37 + (1)/(2) 10 xx t^(2)` `1500 = (500)/(3) xx (3)/(5) t + 5T^(2)` `300 = 20t + t^(2)` On solving, t = 10 s `therefore` horizontal distance `= u cos theta. T` `= (500)/(3) xx (4)/(5) xx 10 = (4000)/(3)m`