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A particle is projected from ground with some initial velocity making an angle of `45^(@)` with the horizontal. It reaches a height of `7.5 m` above the ground while it travels a horizontal distance of `10 m` from the point of projection. The initial speed of the projection isA. `5 m//s`B. `10 m//s`C. `20 m//s`D. `40 m//s` |
Answer» Correct Answer - C `y=x tan theta-g/(2u^(2) cos^(2)theta)x^(2)` |
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