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A particle is projected from ground with velocity `40sqrt(2)m//s` at `45^(@)`. At time `t=2s`A. displacement of particle is `100m`B. vertical component of velocity is `20m//s`C. velocity makes an angle `tan^(-1)(2)` with verticalD. particle is at height of `60m` from ground |
Answer» Correct Answer - A::B::C::D |
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