A particle is projected from the ground with an initial speed v at an angle theta with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is

A particle is projected from the ground with an initial speed v at an

1.	A particle is projected from the ground with an initial speed v at an angle theta with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is
Answer» SOLUTION : R/2 `vecv_(avg) = (vecv+vecu)/(2) = (u COS theta HAT(i) +(u cos theta hat(i)+u sin theta hat(J)))/(2)` ` v_(av) = (v)/(2)SQRT(1+3cos^(2)theta)`