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A particle is projected from the ground with an initial velocity of ` 20 m//s` at angle fo ` 30^@` with the horizontal. What is the magnitude of chang in velocity in `0.5 scond` ? ( g= 10 m//s^2)`. |
Answer» The change in velocity is due to vertical motion of projectile which will be given by ` | Deltavec v| = g Delta t = 10 xx 0.5 =5 m//s`. |
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