A particle is projected from the ground with velocity u making an angle thetawith the horizontal. At half of its maximum heights,

A particle is projected from the ground with velocity u making an angl

1.	A particle is projected from the ground with velocity u making an angle thetawith the horizontal. At half of its maximum heights,
Answer» <html><body><p>its <a href="https://interviewquestions.tuteehub.com/tag/horizontal-1029056" style="font-weight:bold;" target="_blank" title="Click to know more about HORIZONTAL">HORIZONTAL</a> velocity is `<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> cos <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> ` <br/>its vertical velocity is `(u <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a>)` <br/>its velocity is `u((1+ cos^2 theta)/(2))^(1/2)` <br/>all the above are true</p>Answer :D</body></html>