A particle is projected from the ground with velocity u making an angle thetawith the horizontal. At half of its maximum heights.

A particle is projected from the ground with velocity u making an angl

1.	A particle is projected from the ground with velocity u making an angle thetawith the horizontal. At half of its maximum heights.
Answer» its horizontal VELOCITY is a cos `theta` its VERTICAL is `( U sin theta)/(SQRT(2))` its velocity is `u ((1+Cos^(2)theta)/(2))^(1/2)` all the above are true Answer :D